Contoh Soal Menghitung Rangkaian Campuran Resistor
Contoh soal dan jawaban menghitung rangkaian campuran, seri dan pararel resistor. Diketahui rangkaian campuran resistor seperti gambar dibawah ini,
![menghitung_rangkaian_campuran_resistor](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiJcVfNAp8L_ZsTX5r657fzBQ5AAxbN_5q_Ay5pYYigEGrz9tqKllKwixXe11TSzCq9gOTkZ4DHzk9eCTmIg4VLJGVZTs2dBl4Ey7plbrw-o4MPy-loeOuZEbYU3XvWMzw0uNsLSJ2rYrU/s400/menghitung_rangkaian_campuran_resistor.png)
nilai yang diberikan, yaitu:
R1 = 2 Ω
R2 = 8 Ω
R3 = 5 Ω
R4 = 6 Ω
R5 = 2 Ω
R6 = 4 Ω
E = 24 Volt
Hitung berapa nilai Rtotal (Rt), Itotal (It), I1, I2, I3 dan I4?
Penyelesaian:
Sederhanakanlah rangkaian menjadi seperti Gambar 1, lalu gantikan tiap-tiap kelompok resistor menjadi sebuah resistor ekivalen seperti pada Gambar 2 s/d 6.
![rangkaian_ekivalen_rt1](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhoUw6r2tLPCXQPoepjskHBdVEGP37mrH92vIQ0z5jzKt3_b54iIEp_TlyKzCvDf1QWMWzUY18s4VR1V2sbLYE_Ie9bhaew8ZuzdPxOMFCgwuii7BV1yBTpDUf2BhdgHiwfkw7cmbFWYGs/s400/rangkaian_ekivalen_rt1.png)
Rt1 = R5 + R6 = 2 + 4 = 6 Ω
Rt2 = Rt1 || R4 = (Rt1 x R4) ÷ (Rt1 + R4) = (6 x 6) ÷ (6 + 6) = 3 Ω
Rt3 = R3 + Rt2 = 5 + 3 = 8 Ω
![rangkaian_ekivalen_rt2](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhmVtHUiZ96nfWz-g-TKtQpEalH6C1NjiYS7XhUsB5YARMzCeuq8EbB0ljpttLg-zmB7bbOsjUGb6azUR5yNrnpsprHzWBOT-RqucVw4TJeg99NuW5IFwRkEkxqrxJnr4J0suniYauodzU/s400/rangkaian_ekivalen_rt2.png)
Rt4 = Rt3 || R2 = (Rt3 x R2) ÷ (Rt3 + R2) = (8 x 8) ÷ (8 + 8) = 4 Ω
Rt5 = Rt = R1 + Rt4 = 2 + 4 = 6 Ω
![rangkaian_ekivalen_rt4](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhZJwNVUvfhIHAq50IOi3Viuz8e72cv91grkg_dy3zCv2zHyGb2NYmtO-ORhI8PDTFN09g2KYUV6b4z32YEEQkEr3EKSRv7Bd0IotR5LFYxaOmrk1brjB7r9EdJX3xJHndJuCnm9_WMCb0/s400/rangkaian_ekivalen_rt4.png)
sehingga diperoleh
![menghitung_rangkaian_campuran_resistor](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiJcVfNAp8L_ZsTX5r657fzBQ5AAxbN_5q_Ay5pYYigEGrz9tqKllKwixXe11TSzCq9gOTkZ4DHzk9eCTmIg4VLJGVZTs2dBl4Ey7plbrw-o4MPy-loeOuZEbYU3XvWMzw0uNsLSJ2rYrU/s400/menghitung_rangkaian_campuran_resistor.png)
nilai yang diberikan, yaitu:
R1 = 2 Ω
R2 = 8 Ω
R3 = 5 Ω
R4 = 6 Ω
R5 = 2 Ω
R6 = 4 Ω
E = 24 Volt
Hitung berapa nilai Rtotal (Rt), Itotal (It), I1, I2, I3 dan I4?
Penyelesaian:
Sederhanakanlah rangkaian menjadi seperti Gambar 1, lalu gantikan tiap-tiap kelompok resistor menjadi sebuah resistor ekivalen seperti pada Gambar 2 s/d 6.
![rangkaian_ekivalen_rt1](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhoUw6r2tLPCXQPoepjskHBdVEGP37mrH92vIQ0z5jzKt3_b54iIEp_TlyKzCvDf1QWMWzUY18s4VR1V2sbLYE_Ie9bhaew8ZuzdPxOMFCgwuii7BV1yBTpDUf2BhdgHiwfkw7cmbFWYGs/s400/rangkaian_ekivalen_rt1.png)
Rt1 = R5 + R6 = 2 + 4 = 6 Ω
Rt2 = Rt1 || R4 = (Rt1 x R4) ÷ (Rt1 + R4) = (6 x 6) ÷ (6 + 6) = 3 Ω
Rt3 = R3 + Rt2 = 5 + 3 = 8 Ω
![rangkaian_ekivalen_rt2](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhmVtHUiZ96nfWz-g-TKtQpEalH6C1NjiYS7XhUsB5YARMzCeuq8EbB0ljpttLg-zmB7bbOsjUGb6azUR5yNrnpsprHzWBOT-RqucVw4TJeg99NuW5IFwRkEkxqrxJnr4J0suniYauodzU/s400/rangkaian_ekivalen_rt2.png)
Rt4 = Rt3 || R2 = (Rt3 x R2) ÷ (Rt3 + R2) = (8 x 8) ÷ (8 + 8) = 4 Ω
Rt5 = Rt = R1 + Rt4 = 2 + 4 = 6 Ω
![rangkaian_ekivalen_rt4](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhZJwNVUvfhIHAq50IOi3Viuz8e72cv91grkg_dy3zCv2zHyGb2NYmtO-ORhI8PDTFN09g2KYUV6b4z32YEEQkEr3EKSRv7Bd0IotR5LFYxaOmrk1brjB7r9EdJX3xJHndJuCnm9_WMCb0/s400/rangkaian_ekivalen_rt4.png)
sehingga diperoleh
- Rt = 6 Ω
- It = E ÷ Rt = 24 V ÷ 6 Ω = 4 A
- I1 = (Rt4 ÷ R2) x It = (4 ÷ 8) x 4 = 2 A
- I2 = (Rt4 ÷ Rt3) x It = (4 ÷ 8) x 4 = 2 A
- I3 = (Rt2 ÷ R4) x I2 = (3 ÷ 6) x 2 = 1A
- I4 = (Rt2 ÷ Rt1) x I2 = (3 ÷ 6) x 2 = 1A
:c:
BalasHapussaya kurang begitu paham tentang resistor, dengan artikel anda membuat wawasan saya jadi bertambah tentang hal yang berhubungan dengan elektronika. terimakasih ilmunya dan salam sahabat.
BalasHapusElektronika dasar :)
BalasHapusnice post
BalasHapus